nilai dari 2Log12 - 3Log2 - 2Log3 - 3Log18 adalah...
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Jawaban:
[tex]^{2} log12 - ^{3} log2 - ^{2} log3 - ^{3} log18 \\ = ^{2} log \: (3 \times 4) - ^{3}log2 - ^{2} log3 - ^{3} log(9 \times 2) \\ = ^{2} log3 + ^{2} log {2}^{2} - ^{3} log2 - ^{2} log3 - (^{3} log {3}^{2} + ^{3} log2) \\ = ^{2} log3 + 2 - ^{3} log2 - ^{2} log3 - 2 - ^{3} log2 \\ = - 2 ^{3} log2[/tex]
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